第三章作业(答案)

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#第一文档网# 导语】以下是®第一文档网的小编为您整理的《第三章作业(答案)》,欢迎阅读!
作业,答案,第三章

3.1 (a) 0 3.2 (a) 1 3.11

(b) 0 (c) 1 (d) undefined (e) undefined (f) undefined (g) 1 (h) undefined

(b) 1 (c) 0 (d) undefined (e) undefined (f) undefined (g) 0 (h) undefined

功能表:

ABCD 0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 1100 1101 1110 1111



逻辑原理图:

Q1 Off Off Off Off Off Off Off Off On On On On On On On On

Q2 On On On On On On On On Off Off Off Off Off Off Off Off

Q3 Off Off Off Off On On On On Off Off Off Off On On On On

Q4 On On On On Off Off Off Off On On On On Off Off Off Off

Q5 Off On Off On Off On Off On Off On Off On Off On Off On

Q6 On On Off Off On On Off Off On On Off Off On On Off Off

Q7 Off Off On On Off Off On On Off Off On On Off Off On On

Q8 On Off On Off On Off On Off On Off On Off On Off On Off

Z 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0



3.21

High-state DC noise margin = VOHmin - VIHmin = 4.75 - 3.5 = 1.25 (V) Low-state DC noise margin = VILmax - VOLmax = 1.5 - 0.25 = 1.25 (V) 3.27

Vcc

(b) VThev = Vcc×R2 / (R1+R2)

= 5×330 / (330+270)

Vin1 = 2.75V ISC = Vcc / R1

RThev = VThev / ISC

= R1×R2 / (R1+R2) = 270×330 / (270+330) = 148.5Ω

74HC00

Vin2

Vo

R2 330Ω

Vcc

R1 270Ω


VOHmin = 3.84V IOH = (VOHmin-VThev ) / RThev 7.3 mA > IOHmax = 4 mA VOLmax = 0.33V IOL = (VThev - VOLmax) / RThev 16.3 mA > IOLmax = 4 mA 因此,超出了商用工作范围。







Vcc Vcc

(d) VThev = Vcc×R2 / (R1+R2)

= 5 / 2

R1

= 2.5V Vin1 470Ω

Vo ISC = Vcc / R1

74HC00

RThev = VThev / ISC

R2 Vin2 = R1×R2 / (R1+R2)

470Ω

= 470 / 2 = 235Ω

VOHmin = 3.84V IOH = (VOHmin-VThev ) / RThev 5.7 mA > IOHmax = 4 mA VOLmax = 0.33V IOL = (VThev - VOLmax) / RThev 9.2 mA > IOLmax = 4 mA 因此,超出了商用工作范围。 3.49

(a) 根据表3-10

74LSIOLmax = 8 mA74ASIILmax = -0.5 mA Low-state Fan-Out = 8 / 0.5 = 16

74LSIOHmax = -400μA74ASIIHmax = 20μA High-state Fan-Out = 400 / 20 = 20 因此,总的最大扇出为16

高态剩余驱动能力 = (20-16)×20 = 80μA

(b) 根据表3-10

74LSIOLmax = 8 mA74FIILmax = -0.6 mA Low-state Fan-Out = 8 / 0.6 13

74LSIOHmax = -400μA74FIIHmax = 20μA High-state Fan-Out = 400 / 20 = 20 因此,总的最大扇出为13

高态剩余驱动能力 = (20-13)×20 = 140μA 3.56

(a) 根据表3-7和表3-10

74HCTVOHminT = 3.84V74LSVIHmin = 2.0V High-state Noise Margin : 3.84 2.0 = 1.84V 74HCTVOLmaxT = 0.33V74LSVILmax = 0.8V Low-state Noise Margin : 0.8 0.33 = 0.47V

(b) 根据表3-6和表3-10

74ALSVOHmin = 2.7V74HCTVIHmin = 2.0V High-state Noise Margin : 2.7 2.0 = 0.7V

74ALSVOLmax = 0.5V74HCTVILmax = 0.8V Low-state Noise Margin : 0.8 0.5 = 0.3V




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